the length and breadth of a rectangular field are in the ratio 5:3 if its perimeter is 128 M find the dimensions of the field
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Answered by
4
Let the Length and breadth be 5X and 3X
Perimeter of the field = 128
2(L+B) = 128
2(5X+3X) = 128
2 × 8X = 128
8X = 128/2
8X = 64
X = 64/8
X = 8.
Therefore,
Length of the field = 5X = 5 × 8 = 40 CM
Breadth of the field = 3X = 3 × 8 = 24 CM.
aryanbhagat85:
I don't understand
Answered by
3
Let. l:b=5:3
5x&3x
perimeter of rectangle=2(l+b)
128=2(5x+3x)
128=2(8x)
128/2=8x
64=8x
64/8=x
8=xor
x=8
5x=5×8=40,
3x=3×8=24,
so,the dimension of 24&40
5x&3x
perimeter of rectangle=2(l+b)
128=2(5x+3x)
128=2(8x)
128/2=8x
64=8x
64/8=x
8=xor
x=8
5x=5×8=40,
3x=3×8=24,
so,the dimension of 24&40
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