Question

the length and breadth of a rectangular field of the village are 20 m and 15 m respectively. for construction of pillar in the 4 corners of that field 4 cubic holes having length of 4 m are dug out and the soils removed are dispersed on the remaining lend. let us calculate and write the height of the surface of the field that is increased by.​

Answer 1

Step-by-step explanation:

Given The length and breadth of a rectangular field of the village are 20 m. and 15 m. respectively For construction of pillars in the 4 corners of that field 4 cubic holes having length of 4 m. are dug out and the soils removed are dispersed on the remaining land. Let us calculate and write the height of the surfaces of the field that is increased by

So length of the rectangular field = 20 m

Breadth of the rectangular field = 15 m

Corners of each cubic hole = 4m

So total number of cubic holes = 4

Now volume of soil deposited on the rectangular field = total volume of soil taken out of 4 cubical holes.

So we have

           20 x 15 x h = 4 x 4 cube

              300 h = 4 x 4^3

              300 h = 256

               Or h = 256 / 300

             Or h = 0.853 m

Answer 2

Answer:

0.85[approx]

Step-by-step explanation:

The volume of soil of one hole = 4 3 =43 cu-m = 64 cm ∴ ∴ the volume of soil of 4 holes = 64 × 4 =64×4 cu - m = 256 cu -m Let the height of the surface of the field be increased by h metres. ∴ ∴ the volume of the soil thus increased = 20 × 15 × h =20×15×h cu- metres As per condition 20 × 15 × h = 256 20×15×h=256 or , h = 256 20 × 15 = 0.85 h=25620×15=0.85 metre ( approx)