Math, asked by anchal1146, 1 year ago

The length and breadth of a rectangular hall are 50m and 30 m respectively Rectangular tiles with length 50 CM and breadth 40 CM are to be paved on its floor find the number of tiles required

Answers

Answered by PADMINI
8

Given :


Length of Rectangular hall = 50 m


Breadth of Rectangular hall = 30 m


Finding Area of Rectangular hall -


Area = length x breadth


Area = 50 m x 30 m


Area = 1500 metre²


Area of a Rectangular hall = 1500 metre²


Given :


Length of each tile = 50 cm


Breadth of each tile = 40 cm


Converting CM to M -


1 metre = 100 cm .


50 cm = 50/100 = 0.5 m


40 cm = 40/100 = 0.4 m .


Finding Area of each tile -


Area = length x breadth


Area = 0.5 m x 0.4 m


Area = 0.2 metre²


Area of each tile = 0.2 metre² .


Finding number of tiles required -


If , each tile = 0.2 metre² .


1500 metre² = ? tiles


= 1500 / 0.2 = 7500


= Area of 1500 metre² required 7500 tiles tiles.



Answer : Number of tiles Required = 7500 .


Answered by Anonymous
4

 \huge \underline \mathbb {SOLUTION:-}

Given:

  • The length and breadth of a rectangular hall are 50m and 30 m.

Need To Find:

  • Area of rectangular hall = ?

Formula used here:

  • Area = L × B

Putting the values according to the given formula:

➠ Area = 50m × 30m

Area = 1,500m²

  • Hence, the area of rectangular hall is 1,500m²

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Now,

Given:

  • Rectangular tiles with length 50 CM and breadth 40 CM.

Need To Find:

  • Area of each tile = ?

Firstly,we have to convert centimetre to metre.

As we know that,

  • 1m = 100cm

Therefore,

➠ 50cm = 50/100

0.5m

➠ 40cm = 40/100

0.4m

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Now,

  • Find the area of each tile. = ?

Formula used here:

  • Area = L × B

Putting the values according to the given formula:

➠ Area = 0.5m × 0.4m

Area = 0.2m².

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Now,

We have to find the number of each tile. = ?

Suppose, each tile = 0.2m².

Then, 1500m² = ? Tiles

➠ 1500/0.2

7,500

  • Hence, area of 1,500m² required 7,500 number of tiles.

Additional Information:

Here:

  • L is used for Length.
  • B is used for Breadth.

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