the length and breadth of a rectangular park are in the ratio of 7:5.A2 m wide path is running all around outside of the park, the area of the path is 448m^2 find the length (1)length of the park (2)breadth of the park
Answers
Given:-
- the length and breadth of a rectangular park are in the ratio of 7:5
Let x be the common multiple of this ratio.
Length = 7x m
Breadth = 5x m
To find :-
- Area of the rectangular park
Area of the rectangular park = L × B
Area = (7x) (5x)
Area = 35x²
Given :-
- a 2 m wide path is running all around outside of the park
- the area of the path is 448m^2 find the length
To find :-
- Length of the park
- Breadth of the park
Solution:-
As mentioned in the question, "a 2 m wide path is running all around outside of the park" the length and breadth of the path = 2m, we can assume it to be in shape of a square.
Length of the park including the 2 m wide path,
Length = 7x + 2 + 2 = 7x + 4m
Breadth of the park including the 2 m wide path,
Breadth = 5x + 2 + 2= 5x + 4m
Now, let's calculate the area of the park including the dimensions of the path,
Area of the park = l × b
448 = (7x + 4 ) (5x + 4) - 35x²
448 = 7x (5x + 4) 4 (5x + 4) - 35x²
448 = 35x² + 28x + 20x + 16 -35x²
448 = 35x² + 48x + 16 - 35x²
448 = 48x + 16
448 - 16 = 48x
432 = 48x
48x = 432
x =
Substitute the value of x in the values of length and breadth.
We are mainly dealing with the dimensions of the rectangular park, so the verification is also for the same.
Given :-
- the length and breadth of a rectangular park are in the ratio of 7:5
Length = 63 m
Breadth = 45 m
Ratio = 7:5
Length : Breadth = 7:5
=
=
Dividing LHS by 9,
=
LHS = RHS.
Hence answer is verified!
Step-by-step explanation:
length 63 cm. breadth 45 cm