Question

The length and breadth of a rectangular park are in the ratio 4 : 3 and its perimeter is 56 m . Area of field is (step by step guide )​

Answer 1

Given:-

=>Length and breadth of a rectangular park are in the ratio 4:3.

=>Perimeter of the field=56m

To find:-

=>Area of the field.

Solution:-

=>Let the length and breadth be 4x and 3x respectively.

=>Perimeter of a rectangle=2(l+b)

=>2(4x+3x)=56

=>8x+6x=56

=>14x=56

=>x=56/14

=>x=4

Thus-----

i.Length of the field=4(4)=16m

ii.Breadth of the field=3(4)=12m

=>Area of a rectangle=l×b

=>16m×12m

=>192m²

Thus,area of the field is 192m².

Answer 2

Step-by-step explanation:

$\huge\sf\underline{\underline{\pink{✤ Question:-}}}$

The length and breadth of a rectangular park are in the ratio 4 : 3 and its perimeter is 56 m . Area of field

$\huge{\underline{\red{✒to \: find:-}}}$

Area of field.

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Perimeter of rectangular park =56 m [ given ]

• perimeter of rectangle:

$\sf\underline{\underline{\purple{2(length + breadth)}}}$

let length and breadth of park =3x and 4x

our equation:

56=2(3x+4x)

=>56/2=7x

=>28=7x

=>x=28/7

=>x=4

length of park = 3x = 3×4 =12 m

breadth of park=4x= 4×4 =16 m

• area of rectangle:

$\sf\underline{\underline{\purple{length \times breadth}}}$

area of rectangular park=(12×16) m^2

=192 m^2

$\sf\underline{\underline{\purple{area\: of\: rectangular \:park = 192{m}^{2}}}}$