Question

the length and breadth of a rectangular park are in the ratio 7:5and its perimeter is 120m find the cost of surrounding the park on its outside by a uniformly broad path of 1m at the raye of₹22.50 per sq m.​

Answer 1

Answer:

The cost of surrounding the park on its outside a uniformly broadpath is Rs.2790.

Step-by-step explanation:

Given : The length and breadth of a rectangular park are in ratio 7 is to 5 and its perimeter is 120 m.

To find : The cost of surrounding the park on its outside a uniformly broad path of 1 m at rupees 22.50 per square meter ?

Solution :

The length and breadth of a rectangular park are in ratio 7 : 5.

Let l=7x and b=5x

Perimeter = 120 m

Perimeter is given by,

P=2(l+b)P=2(l+b)

120=2(7x+5x)120=2(7x+5x)

120=2(12x)120=2(12x)

120=24x120=24x

x=\frac{120}{24}x=

24

120

x=5x=5

The length is l=7x=7(5)=35 m

The breadth is b=5x=5(5)=25 m

Surrounding the park on its outside a uniformly broadpath of 1 m.

So, Length became l=35+1+1=37 m

Breadth became b=25+1+1=27 m

Area of boarding = Outer area - Inner area

Area of boarding = 37\times 27-35\times 2537×27−35×25

Area of boarding = 999-875999−875

Area of boarding = 124 m²

The cost is given by at rupees 22.50 per square metre is

C=22.50\times 124C=22.50×124

C=Rs.2790C=Rs.2790

The cost of surrounding the park on its outside a uniformly broadpath is Rs.2790.