The length and breadth of a rectangular park is in the ratio 5:4. The cost of fencing the park at the rate of rupees 50 per metre will be rupees 4950. Find the length and breadth of the park.
Answers
Answer:
The length and breadth of the park are 27.5 m and 22 m respectively.
Step-by-step explanation:
Let the length and breadth of a rectangular park be 5x and 4x respectively.
Given:
Cost of fencing 1 m park = Rs 50
Let Cost of fencing y m park = Rs 4950
So, 1/y = 50/4950
→ y = 4950/50
→ y = 99
Formula: P = 2(l + b) unit
According to question:
2(5x + 4x) = 99
→ 2 × 9x = 99
→ 18x = 99
→ x = 5.5
∴ Dimensions of park:
Length = 5x = 5 × 5.5 = 27.5 m
Breadth = 4x = 4 × 5.5 = 22 m
Abbreviations used:
P = Perimeter of rectangle
l = Length of rectangle
b = Breadth of rectangle
➙ The dimensions of the park is :
- length = 27.5 metres
- breadth = 22 metres.
Given that,
The dimensions of a park is in ratio 5 : 4. The cost of fencing the park is ₹4,950 at the rate of ₹50 per metre.
Here, the rate and the total cost of fencing is given and also, dimensions are in the ratio.So,we need to find it's actual dimensions.
Step 1 :
Let's consider, the dimensions :
- Length = ‘5x’
- Breadth = ‘4x’
The park is in rectangle shape. Fencing of the park means the perimeter of the park.
We know that,
Perimeter of a rectangle = 2(l + b)
- l (length) = ‘5x’
- b (breadth) = ‘4x’
So,
→ 2(5x + 4x)
→ 2(9x)
→ 18x
Step 2 :
Perimeter of the rectangle is given by :
→
- Total cost of fencing is ₹4,950 (given)
- Rate is ₹50 per metre (given)
So,
→
→ 99 metres.
Step 3 :
Now we are getting two perimeters :
- One as variable i.e., ‘18x'
- As numerical i.e., ‘99 metres’
we can say that,
→ 99 = 18x
→ = x
→ x = 5.5
∴ The value of ‘x’ is 5.5 metres
The dimensions are :
- length = 5x = 5(5.5) = 27.5 metres.
- breadth = 4x = 4(5.5) = 22 metres.