Question

The length and breadth of a rectangular photo frame are 0.3 m and 40 cm respectively. So the distance between its two opposite corners is ​

Answer 1

Since angle b/w sides of a rectangle is 90°
Therefore using pythagoras theorem
{(0.3m)^2+(40cm)^2 }^1/2
{(30cm)^2+(40cm)^2}^1/2
{900+1600}^1/2
2500^1/2
50 cm
Therefore the disatnce b/w opposite corners is 50cm

Answer 2

$\sf\underline{Step-by-step \: explanation}$



Let the diagonal be x (Opposite sides can be a diagonal)



0.3 metres = 30cm (1 m = 100 cm)



As the rectangle is 90°, We can use Pythagoras' theorem.




${hp}^{2} = {b}^{2} + {p}^{2}$


${x}^{2} = {40}^{2} + {30}^{2}$

${x}^{2} = {1600} + 900$


${x}^{2} = \sqrt{2500}$

$x \: = 50$


Hence, the hypotenuse is 50 cm.



So, the length between the two sides will be 50 cm.