Question

The length and breadth of a rectangular plate are measured to be 14,5 cm and 2.1 cm respectively. The area of the plate up to correct significant figures is
32 cm2
3.0 x 10 cm2
30.4 cm2
30.45 cm2​

Answer 1

Answer:

Solution

A=2×(L×B+B×T+T×L)

∴A=2×(4.234×1.005+1.005×0.0201+0.0201×4.234)

∴A=2×(4.2552+0.0202+0.0851)

∴A=8.721m2

∴A=8.721m2  to correct significant digits

V=L×B×T

∴V=4.234×1.005×0.0201

∴V=0.0855m3 to correct significant digits

Explanation:

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Answer 2

Answer:

Explanation:

Here length = 14.5 cm → 3 significant figures.

breadth =4.2 cm → 2 significant figures.

∴ Area = 14.5×4.2cm2

=60.90cm2

The answer should be rounded off to two significant figures.

∴ The digit to be dropped in the answer 60. 9 0 is 9 (circled ) which is greater than 5. So the preceding zero is raised by 1.

hence the answer 61cm2