the length and breadth of a rectangular plot are in ratio 5 : 3 if the area of the plot is 2940 m^2 ,find the cost of fencing the boundary of the plot at the rate of Rs.5.70 per metre
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Answers
Answered by
16
Heyy Buddy ❤
Here's your Answer...
Let the length and Breadth be 5x and 3x respectively.
=> Area of plot = l × b
=> 2940 = 5x × 3x
=> 2940 = 15x^2
=> x^2 = 2940/15
=> x^2 = 196
=> x = 13 m.
Length = 5x = 5 × 13 = 65m
Breadth = 3x = 3. × 15 = 45m.
Fencing a boundary means PERIMETER.
=> PERIMETER of plot = 2( l + b)
=> 2( 65 + 45)
=> 2 × 110
=> 220m.
Cost For fencing 1 m = 5.70
=> Cost for fencing 220 m = 220 × 5.70
=> 1254 Rupeee.
✔✔✔
Here's your Answer...
Let the length and Breadth be 5x and 3x respectively.
=> Area of plot = l × b
=> 2940 = 5x × 3x
=> 2940 = 15x^2
=> x^2 = 2940/15
=> x^2 = 196
=> x = 13 m.
Length = 5x = 5 × 13 = 65m
Breadth = 3x = 3. × 15 = 45m.
Fencing a boundary means PERIMETER.
=> PERIMETER of plot = 2( l + b)
=> 2( 65 + 45)
=> 2 × 110
=> 220m.
Cost For fencing 1 m = 5.70
=> Cost for fencing 220 m = 220 × 5.70
=> 1254 Rupeee.
✔✔✔
Answered by
7
Answer:
Step-by-step explanation:
Length:breath = 5:3.
Let, length = 5x
Breath = 3x
Area of the plot = l×b
2940 =5x × 3x
2940 = 15x^2
2940/15 = x^2
196 =x^2
_/196 =x
13m =x
Therefore, length=5x= 5×13 = 65m
Breadth= 3x = 3×13 = 39m
Perrimeter of the plot= 2 (l+b)
= 2 (65+39)
= 2 ×104
= 208m
Cost= rate×perimeter
= 5.70×208
= rs 1185.5
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