Question

the length and breadth of a rectangular plot is 10.15 M and 9.75 M respectively .how much fencing will be required for the plot ?​

Answer 1

length=10.15m

breadth=9.75m

perimeter(fencing)=2×(l+b)=2×(10.15+9.75)=39.8

Answer 2

Answer:

$39.8$ m fencing will be required for the plot.  

Step-by-step explanation:

Given : Length of rectangular plot = $10.15$ m

           Breadth of rectangular plot = $9.75$ m

To find : How much fencing will be required for the plot ?​

Solution :

• It is given that, Length of rectangular plot = $10.15$ m

           Breadth of rectangular plot = $9.75$ m

• We have to find the total fencing required for the plot.
• We know that fencing is done at the boundary of the rectangular plot.
• To find total fencing required for the plot, we have to calculate perimeter of the rectangular plot.
• We know that perimeter is the sum of all sides of a plot.

      ∴ Perimeter of the plot = $2(length+breadth)$

                                        = $2(10.15+9.75)$

                                        = $2*19.90$

                                        = $39.8$ m

• ∴ $39.8$ m fencing will be required for the plot.