the length and breadth of a rectangular tank are 3.0 and 2.0 m it contains Water Up to The height of 1.5m Calculate the Total Thrust and Pressure at the bottom of the tank Due to Water . Density of Water =1000 kg/m^3 and g = 10 m/s^2
Answers
We are given the dimensions of the tank. From that we can find its volume that is
Length x Breadth x height
= 3 x 2 x 1. 5
= 9m^3
Now we know that
Density = Mass/volume
=》1000kg/m^3=mass/9m^3
=》mass=9000kg
Now, Force = mass x acceleration
=9000kg X 10m/s^2
(g=10m/s^2)
=90000 Newton
Now , Area of the bottom of tank
= length x breadth
=3 m x 2m
= 6m^2
Therefore,
PRESSURE= FORCE/AREA
=90000 Newton/
6m^2
=15000 PASCAL
or
15000 Newton/ m^2
Answer:
force = 9 × 10^4 N
pressure = 1.5×10^4 N/m^2
Explanation:
length= 3.0 m
width= 2.0 m
height = 1.5 m
volume = l× w × h =3×2×1.5=9.0
force=volume×density× gravitational acceleration
=Vpg
=9×1000×10
=9×10^4 N or 90000N
pressure=force/area
area=l×w =3×2 = 6
P = F/A = 90000/ 6 = 15000 or 1.5×10^4 N/m^2