Question

The length and breadth of a rectangular tank are 3m and 2m respectively. It contains water upto a height of 1.5m. Calculate the total thrust and pressure at the bottom of the tank.​

Answer 1

Answer:

Pressure (P) at the bottom of the tank is given by P=hdg

=1m×1000kg×9.8ms−2=9800Nm−2

Surface area at the bottom of the tank =2m×1.5m=3m2

∴Thrustatthebottomofthetank=force×area

=9800Nm−2×3m2=29,400N.

$Pressure (P) at the bottom of the tank is given by P=hdg</p><p>=1m×1000kg×9.8ms−2=9800Nm−2</p><p>Surface area at the bottom of the tank =2m×1.5m=3m2</p><p>∴Thrustatthebottomofthetank=force×area</p><p>=9800Nm−2×3m2=29,400N.</p><p></p><p>$

Answer 2

heya!!!❤️

Pressure (P) at the bottom of the tank is given by P=hdg

=1m×1000kg×9.8^-2ms

=9800Nm ^−2

Surface area at the bottom of the tank =2m×1.5m=3m²

∴Thrust at the bottom of the tank=force×area h

=9800NM-²×3m²

=29,400N.