Question

the length and breadth of a room 15/2m and 31/6 m find the perimeter of the room . please do fast​

Answer 1

Answer:

perimeter = 2(15/2+31/6)

2(45+31/6)

2(76/6)

76/3

25.33....

Answer 2

Answer:

Given :-

Length (l) = $\frac{15}{2}m$

Breadth (b) = $\frac{31}{6} m$

Formula :-

$\green{p \: = \: 2(l+b)$

Solution :-

$p \: = \: 2(\frac{15}{2} + \frac{31}{6})\\ \\LCM \: of \: 2 , 6 = 6\\\\ p = 2( \frac{45 + 31}{6} )\\\\p=2(\frac{76}{6})\\\\p=(\frac{76}{3}) \\\\\red{p=25.33m}$

Hope it helps you!!