Question

The length and breadth of a room are 18 m and 8 m respectively. Find the cost of covering the floor with tiles at the rate of ₹ 100 per sq. m.

Answer 1

Solution

Given :-

• Length of rectangular room = 18 m
• Breadth of rectangular room = 8 m
• Cost of covering floor by tiles of 1 m² = 100

Find :-

• Total cost of covering floor by tiles.

Explanation

Formula

$\dag\boxed{\underline{\mathfrak{\red{\:Area_{rectangle}\:=\:(Length\times Breadth)}}}}$

So First Calculate Area of rectangular room,

==> Area of rectangular room = 18 × 8

==> Area of rectangular room = 144 m².

_________________________

∵ coat of covering room by tiles of 1 m² = 100

•°• cost of covering room by tiles of 144 m² = 144×100

•°• cost of covering room by tiles of 144 m² = 14,400

Hence

• Total cost will be = 14,400 rupees .

_________________

Answer 2

Given : The length and breadth of a room are 18 m and 8 m respectively and the cost of covering the floor with tiles at the rate of ₹ 100 per sq. m.

Need To Find : The cost of covering the floor with tiles.

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❍ Finding Area of the floor of Room by the formula is given by :

⠀⠀⠀⠀⠀⠀⠀⠀

⠀⠀⠀⠀⠀⠀⠀⠀$\pink{\boxed{\sf{ Area _{(Rectangle)} = l \times b \:}}}$

⠀⠀⠀⠀Here l is the length of Rectangle in metres and b is the Breadth of Rectangle in metres and we have given with length and breadth of a room are 18 m and 8 m respectively .

⠀⠀⠀⠀⠀⠀⠀⠀

⠀⠀⠀⠀⠀⠀$\underline {\frak{\bf{\star\:Now \: By \: Substituting \: the \: Given \: Values \::}}}$

⠀⠀⠀⠀⠀⠀⠀⠀

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀$:\implies {\mathrm {Area_{(Floor\:of\:Room)}  = 18 \times 8   }}$

⠀⠀⠀⠀⠀$\underline {\boxed{\pink{ \mathrm {  Area_{(Floor\:of\:Room)} = 144 \: m^{2}}}}}$

⠀⠀⠀⠀⠀⠀⠀⠀

Therefore,

⠀⠀⠀⠀⠀$\underline {\therefore\:{\pink{ \mathrm {  Area\:of\:Room\:is\: 144\:m^{2} }}}}$

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀━━━━━━━━━━━━━━━━━━━⠀⠀⠀⠀

⠀⠀⠀⠀⠀⠀⠀⠀

❍ Finding Cost of covering the floor of Room with tiles by the formula is given by :

⠀⠀⠀⠀⠀⠀⠀⠀

⠀⠀⠀⠀⠀$\pink{\boxed{\sf{Total\: Cost = Area\:of\:floor\times Cost\:at\:the\:rate\:of\:m^{2} \:}}}$

⠀⠀Here Area of Room is 144 m² and the Cost at rate of per sq.m is Rs.100 per sq.m .

⠀⠀⠀⠀⠀⠀⠀⠀

⠀⠀⠀⠀⠀⠀⠀⠀

⠀⠀⠀⠀⠀⠀$\underline {\frak{\bf{\star\:Now \: By \: Substituting \: the \: Given \: Values \::}}}$

⠀⠀⠀⠀⠀⠀⠀⠀

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀$:\implies {\mathrm {Total \:Cost\: = 144 \times 100   }}$

⠀⠀⠀⠀⠀$\underline {\boxed{\pink{ \mathrm {  Total\:Cost\: =\:Rs.\; 14400\: m^{2}}}}}$

⠀⠀⠀⠀⠀⠀⠀⠀

Therefore,

⠀⠀⠀⠀⠀$\underline {\therefore\:{\pink{ \mathrm {  Total\:Cost\:\:of\:Room\:flooring\:with\:tiles\:is\: Rs.14400\: }}}}$

⠀⠀⠀⠀⠀⠀⠀⠀

⠀⠀⠀⠀⠀⠀⠀⠀━━━━━━━━━━━━━━━━━━━⠀⠀⠀⠀

$\qquad\quad\boxed{\bf{\mid{\overline{\underline{\blue{\bigstar\: More \: to \; know\: :}}}}}\mid}$

• $\longrightarrow  {\sf{ Perimeter _{( Triangle)} = Side\:A+Side\:B+Side \:C \:units .}}$

• $\longrightarrow  {\sf{ Perimeter _{( Rectangle)} = 2( Length + Breadth)\:units .}}$

• $\longrightarrow  {\sf{ Perimeter _{( Square)} = 4 \times Side \:units .}}$

• $\longrightarrow  {\sf{ Circumference _{( Circle)} = 2 \times\pi \times Radius \:units .}}$

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