Math, asked by shiningnon, 11 months ago

the length and breadth of a room are 2500m and 1200m respectively.find the cost to cover it with tiles having an area of 50 sq.m at the rate of rs 2.5 each​

Answers

Answered by dhruvshembekar12
0
₹1,50,000 this is the cost to cover the floor with tiles
Answered by TRISHNADEVI
1

 \huge{ \underline{ \overline{ \mid{ \mathfrak{ \purple{ \:   \: SOLUTION \:  \: } \mid}}}}}

 \underline{ \mathfrak{ \:  \: Given, \:  \: }} \\  \\   \red{\text{Length of the room, l = 2500 m }} \\   \red{\text{Breadth of the room, b = 1200 m}}

 \underline{ \mathfrak {\: We  \:  \: know \:  \:  that, \:  \: }} \\  \\  \boxed{ \bold{ \pink{ \:  \: Area  \:  \: of \:  \:  a \:  \: rectangle = Length \times Breadth}}}

 \tt{ \therefore \:  \:  \red{Area  \:  \: of \:  \:  the  \:  \: room} = l \times b} \\  \\  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \tt{ = (2500 \times 1200)  \: \: m {}^{2} } \\  \\   \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:    \tt{=  \red{3000000 \:  \: m {}^{2} }}

 \mathfrak{ \: Again, } \\  \:  \:  \:  \:  \:  \:  \:  \:  \: \underline {\mathfrak{ \: Given  \:  \: that, \: }} \\  \\   \:  \:  \:  \:  \:  \:  \:  \: \red{ \tt{Area   \: \: of  \:  \: each  \:  \: tile = 50 \:  m {}^{2} }} \\  \\  \tt{No. \:  of \:  \:  required  \:  \: tiles =  \frac{Area   \: \: of  \:  \: the  \:  \: room}{Area   \: \: of  \:  \: each  \:  \: tile} } \\  \\   \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \tt{ =  \frac{3000000}{50} } \\  \\\:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:   \tt{ = \red{60000}}

 \mathfrak{Now,} \\  \\   \:  \:  \:  \:  \:  \: \tt{Cost  \:  \: of \:  \:  each \:  \:  tile = Rs. 2.5} \\  \\  \tt{ \therefore \: Cost \:  \:  of  \:  \: 60000 \:  \:  tiles =Rs.(2.5 \times  60000)} \\  \\   \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: \tt{ = \red{ Rs.150000}}

 \:  \:  \:  \:  \therefore \:  \red{ \text{The cost to cover a room of  length 2500 m }} \\ \red{ \text{ and breadth 1200 \: m with tiles \: having an  }} \\  \red{ \text{area \: of 50 sq.m at the rate of Rs.2.5 \: each \: is}} \\  \text{ \underline{ \pink{ \:Rs.150000 \: }}}

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