Question

the length and breadth of a room are 3 m and 4 m. what is the length of the longest metallic rod that can be placed on the floor?

Answer 1

As the diagonal and the two sides would form a right angled triangle right angled at the intersection of the two walls of the room.
Thus by the Pythagoras theorem
Diagonal^2 = 1st side^2 + 2nd side^
Diagonal^2 = 3^2 + 4^2
diagonal^2 = 25
Diagonal = 5m.

Answer 2

Hiii friend!!

Here's ur answer:-

*The longest rod that can be placed on the floor is known to be diagonal of that floor.

*Since,the floor is in rectangle shape then,the diagonal form a right angle triangle.

*In which diagonal is hypotenuse(longest rod is given), length will be perpendicular & breadth will be base.

=>Now it is given that
length=3m
breadth=4m

By using Pythagoras theorem in right angle triangle,

(hypotenuse)²=(base)²+(perpendicular)²

(hypotenuse)²=(4m)²+(3m)²

(hypotenuse)²=16m²+9m²

(hypotenuse)²= 25 m²

hypotenuse= √25m²

hypotenuse=5m

So,as we considered that the rod is the longest side that means hypotenuse
then the length of rod is 5m


@Altaf