the length and breadth of a room are 3 m and 4 metres. what is the length of the longest metallic rod that can be placed on the floor?
Answers
Answered by
87
Hi ,
Dimensions of room are ,
Length = l = 3 m ,
Breadth = b = 4 m
Length of the Longest rod placed in
the room = length of the diagonal of the floor
= √ l² + b²
= √ 3² + 4²
= √ 9 + 16
= √ 25
= 5
I hope this helps you.
:)
Dimensions of room are ,
Length = l = 3 m ,
Breadth = b = 4 m
Length of the Longest rod placed in
the room = length of the diagonal of the floor
= √ l² + b²
= √ 3² + 4²
= √ 9 + 16
= √ 25
= 5
I hope this helps you.
:)
Anu500:
Hello .....thanks a lot
Answered by
21
Assuming that the room is rectangular in shape, the length of the longest rod that can be placed on the floor would be equal to the length of the hypotenuse formed by the triangle with the sides 3m and 4m long as its sides
Let the hypotenuse be X
X^2=3^2+4^2
X^2=25
Or X = 5
Hence the length of the longest rod would be 5m
Let the hypotenuse be X
X^2=3^2+4^2
X^2=25
Or X = 5
Hence the length of the longest rod would be 5m
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