Question

The length and breadth of a room are 8 m and 6 m respectively. A cat runs along all the four walls and finally
along a diagonal in order to catch a rat. How much total distance is covered by the cat?
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Answer 1

Answer:

from my side the answer is

Step-by-step explanation:

Required distance =8+6+8+6=

8

2

+6

2

=28+

100

28+10

=38m

Answer 2

Question :-

The length and breadth of a room are 8 m and 6 m respectively. A cat runs along all the four walls and finally

along a diagonal in order to catch a rat. How much total distance is covered by the cat?

Answer :-

The total distance covered by the cat ↠ 38 m.

Given :-

• Length of a room = 8m
• Breadth of the room =6m
• A cat runs along all the four walls and finally along a diagonal in order to catch a rat.

Have to Find :-

• How much total distance is covered by the cat?

Solution :-

As we know ,

Perimeter of the Rectangle = 2 ( length + breadth )

 ↬  2 ( 8 + 6 )

↬ 2 × 14

↬ 28m .

Now , we got the perimeter.

So , as we know that diagonal of a rectangle divides the rectangle into two equal right-angled triangles.

Hence,

Here also it divides the room into two equal right - angle triangle .

Let's find out the third side ( hypotenuse )

By using Pythagoras Theorem :- (hypotenuse)²= ( Perpendicular)²+ ( Base )²

(hypotenuse)² = (8)² + (6)² 

↬ 64 + 36

↬ $100$

       

 Hypotenuse = √100 = 10m = Diagonal

  Now , from this the total distance covered by the cat

↬  28m + 10m

↬ 38 m

__________________________

Other Important Formulas :-

↬ Perimeter of Rectangle = 2( L + B )

↬ Perimeter of square = 4 × Side

↬ Perimeter of triangle = AB + BC + CA

↬ Area of Rectangle = L × B

↬ Area of Square = ( side ) ²

↬ Area of Rhombus = Product of Diagonal/2.

↬ Area of Parallelogram = Base × Height.

↬ Area of triangle = 1/2 × base × height .