Math, asked by CHARAN234420, 9 months ago

The length and breadth of a room are in the ratio 3: 2, its area is 216 Sq.m, Find its perimeter?

Answers

Answered by pilotbenets28
1

Answer:

60m

Step-by-step explanation:

The room is in ratio of 3 by 2 with unknown part of a selected room,

so, let, Y , be the unknown part for all complete ratios of 3:2

then, take 3 + 2 = 5 to get the total ratio

then, length L will be equals to 3/5 times Y

        Width(breadth) W will be equals to 2/5 times Y

RECALL: Area = L X W

But given area is 216 sq.m

therefore, substitute the data in the equation,

216 = 3/5timesY × 2/5timesY

216 = 6Y²/25

CROSS MULTIPLICATION,

216×25=6Y²

DIVIDE BY 6 BOTH SIDES

900 = Y²

30 = Y=complete part of the room to get breadth and length.

then, solve for Y, YOU WILL GET 30m

therefore, take 3/5 ×30 to get length, and take 2/5×30 to get breadth

L =18m and W= 12m

so, perimeter = 2L + 2w

    answer = 2×18 + 2×12= 60m

Welcome+255714307162, a physics,science and math teacher.

Similar questions