Question

the length and breadth of ahall are 21 1/3m and 11 1/4 m respectively. how many tiles are required to pave a floor of the hall if square tiles of the side 3/4m are used

Answer 1

Answer:

GIVEN:-

length = 21 (3/4) = 87/4m

breadth = 11 (1/4) = 45/4m

side of square tiles = 3/4m

now,

area of hall = (length × breadth)

= (87/4 × 45/4)

= (3915/16)

= 3915/16 m²

similarly,

area of square tiles = 3/4 × 3/4 = 9/16m²

thus, tiles are required to pave the floor of the hall = area of hall /area of tiles.

=> {(3915/16)m²}/{(9/16)m²}

=> 3915m²/9m²

=> 435 tiles

hence, tiles are required to pave the floor of the hall = 435

Step-by-step explanation:

Answer 2

Step-by-step explanation:

length of hall=

$21 \frac{1}{3}$

breadth=

$11 \frac{1}{4}$

Area of hall =l×b

=

$21 \frac{1}{3} \times 11 \frac{1}{4} \\ = \frac{64}{3} \times \frac{45}{4} = 240 {m}^{2}$

area of square tile=side×side

=

$\frac{3}{4} \times \frac{3}{4} = \frac{9}{16} {m}^{2}$

no. of tiles required =

$\frac{area \: of \: hall}{area \: of \: tile} =240 \div \frac{9}{16} = 240 \times \frac{16}{9} = about \: 426$

426 (approx) tiles are used