Question

The length and breadth of rectangle are 12 cm and 9 cm respectively. Find the side of the square with perimeter equal to the rectangle ​

Answer 1

Given :

• The length and breadth of rectangle are 12 cm and 9 cm respectively

To find :

• the side of the square with perimeter equal to the rectangle

Solution :

l = 12

b = 9

4a = 2 (l + b)

4a = 2 (12 + 9)

4a = 2 × 21

4a = 42

a = 42/4

a = 10.5

Extra information :

• Volume of cylinder = πr²h
• T.S.A of cylinder = 2πrh + 2πr²
• Volume of cone = ⅓ πr²h
• C.S.A of cone = πrl
• T.S.A of cone = πrl + πr²
• Volume of cuboid = l × b × h
• C.S.A of cuboid = 2(l + b)h
• T.S.A of cuboid = 2(lb + bh + lh)

Answer 2

ɢɪᴠᴇɴ:-

• The length of rectangle is 12 cm
• And, the breadth is 9cm respectively.

ᴛᴏ ғɪɴᴅ:-

• The side of the square with perimeter equal to the rectangle

ᴇxᴘʟᴀɴᴀᴛɪᴏɴ:-

We know,

$\longmapsto\tt{\small{\boxed{\bold{\bold{\orange{\sf{Perimeter\:of\:Rectangle=2(l+b)}}}}}}}$

According to the given condition,

4a = 2 (l + b)

4a = 2 (12 + 9)

4a = 2 × 21

4a = 42

a = 42/4

a = 10.5

$\blue\longmapsto\:\large\underline{\boxed{\bf\green{a}\red{=}\pink{10.5}}}$

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