Math, asked by kumarkrishna72628, 7 months ago

the length and breadth of rectangle are 12cm and 9cm respectively. find the side of the square with perimeter equal to that of the rectangle​

Answers

Answered by ayushjha187100
0

Step-by-step explanation:

Area of rectangle with length 16 cm & width 4 cm

=(length)×(width)

=(16)(4)

=64 cm2

2. Area of square of side x= area of rectangle with length 16 cm & width 4 cm

x2=16×4

x2=64

x=64−−√=8

3. Perimeter of square of side x=8 cm is

= 4 x

=4(8)

= 32 c m

hope it will help you...

Answered by Marie1804
0

Answer:

10.5

Step-by-step explanation:

Given:

   Length of rectangle= 12cm

   Breadth of rectangle= 9cm

   Perimeter of rectangle=perimeter of square

Now:

   Perimeter of rectangle= 2(l+b)

                                        = 2(12+9)

                                        = 2*21

                                        = 42

As, P of rectangle= P of square= 42

So, Side of square= 1/4*perimeter of square

                             = 1/4*42

                            =10.5 cm

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