The length and breadth of rectangle are 5.7+-0.1 cm and 3.4+-0.2 cm .calculate area of rectangle with error limits.
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Answered by
694
Length = 5.7 ± 0.1 cm
breadth = 3.4 ± 0.2 cm
A = Lb
= (5.7 × 3.4)
= 19.38 cm²
ΔA = A × (ΔL/L + Δb/b)
= 19.38 × (0.1/5.7 + 0.2/3.4)
= 1.48 cm²
Area of rectangle = (19.38 ± 1.48) cm²
breadth = 3.4 ± 0.2 cm
A = Lb
= (5.7 × 3.4)
= 19.38 cm²
ΔA = A × (ΔL/L + Δb/b)
= 19.38 × (0.1/5.7 + 0.2/3.4)
= 1.48 cm²
Area of rectangle = (19.38 ± 1.48) cm²
Answered by
108
Answer:
The area of the rectangle with error limits is (19.38 ± 1.48) cm.
Given:
Dimensions of a rectangle,
Length,l= 5.7 ± 0.1 cm
breadth,b = 3.4 ± 0.2 cm
To find area of rectangle without the error limits,
We know that area of a square, A = l×b
On substituting the value,
A = (5.7 × 3.4)
= 19.38 cm²
To find the area of rectangle with error limits,
ΔA = A × (ΔL/L +Δb/b)
= 19.38 × (0.1/5.7 +0.2/3.4)
= 1.48 cm²
Finally the area of rectangle with the error limits = (19.38 ± 1.48) cm.
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