Question

The length and breadth of rectangle are 8cm and 6cm respectively. Find the length of the diagonals.​

Answer 1

Answer:

10 cm

Step-by-step explanation:

n ∆ ABC , by phythagoras theorem

AC² = AB²+BA²

AC² =8²+6²

AC²=64+36=100

AC²=100

AC=√100

AC=10cm  

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Answer 2

Given:

• Length (Rectangle) = 8cm
• Breadth (Rectangle) = 6cm

To Find:

• Length of the diagonal?

Formula Used:

$\\ \bigstar{\underline{\boxed{\sf\green{ (Hypotenuse)^2 = (Base)^2 + (Perpendicular)^2 }}}}$

Solution:

We can find diagonal of the rectangle by applying Pythagoras theorem;

• Length (Perpendicular) = 8cm
• Breadth (Base) = 6cm

(H)² = (B)² + (P)²

After substituting values in Formula;

$\colon\implies{\sf{ (H)^2 = (6)^2 + (8)^2 }} \\ \\ \colon\implies{\sf{ (H)^2 = 36 + 64 }} \\ \\ \colon\implies{\sf{ (H)^2 = 100 }} \\ \\ \colon\implies{\sf{ H = \sqrt{100} }} \\ \\ \colon\implies{\sf\red{ H = 10 cm}}$

Hence,

The Diagonal of the rectangle is 10 cm.