Question

The length and breadth of rectangle are 8cm and 6cm respectively. Find the length of the diagonals.​

Answer 1

Answer:

the area is 8×6=48. Am I right?

Answer 2

$\frak{Given} \begin{cases} \sf Length \:of\:rectangle\:is\: = \frak{8\:cm} & \\ \\ \sf Breadth\:of\:rectangle\:is \: = \frak{6\:cm}& \end{cases}$

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❍ Let the height be H.

$\dag\;{\underline{\frak{As\;we\;know\;that,}}}$

$\star\;{\boxed{\sf{\purple{Hypotenuse^2_{\;(Rectangle)} = Base^2 +Perpendicular^2}}}}$

$\colon\implies{\sf{ (H)^2 = (6)^2 + (8)^2 }} \\ \\ \colon\implies{\sf{ (H)^2 = 36 + 64 }} \\ \\ \colon\implies{\sf{ (H)^2 = 100 }} \\ \\ \colon\implies{\sf{ H = \sqrt{100} }} \\\\\\ :\implies{\boxed{\frak{\pink{H = 10}}}}\:\bigstar$

${\therefore\pmb{\underline{\sf{ The \ length \ of \ the \ diagonal \ is \purple{\ 10\:cm .} }}}}$

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