Question

the length and breadth of rectangle are in ratio 4:3. if diagonal measures 25m then the parameter of rectangle is

Answer 1

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Here is your answers

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Let the rectangle of breadth be 3x. and length be 4x

${d}^{2} = {l}^{2} + {w}^{2} \\ \\ {d}^{2} = {(4x)}^{2} + {(3x)}^{2} \\ \\ {d}^{2} = 16 {x}^{2} + 9 {x}^{2} \\ \\ d = \sqrt{ {25x}^{2} } \\ \\ 25 \: = 5x \\ \\ x = \frac{25}{5} = 5 \\ \\ length \: of \: rectangle \: be \: 4x = 4 \times 5 = 20cm \: \\ \\ breadth \: = 3x = 3 \times 5 = 15cm$


Therefore perimeter of rectangle

= 2(l + b)

= 2( 20+15)

= 2(35)

= 70cm ...


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Answer 2

$\boxed{ANSWER..}$

Let ABCD be a rectangle.

Let the length of the rectangle be 4x and the breadth of the rectangle be 3x respectively.

The length of the diagonal = 25m

From the rectangle along with the diagonal ,

In ∆ABC ,

AB = 4x , BC = 3x , AC = 25m

(AC)^2 = (AB)^2 + (BC)^2

(25)^2 = (4x)^2 + (3x)^2

625 = 16x^2 + 9x^2

625 = 25x^2

x^2 = 625/25

x^2 = 25

x = √25

x = 5m

Therefore ,

The length of the rectangle = 4x = 4×5

= 20 m

The breadth of the rectangle = 3x = 3×5

= 15m

So ,

The perimeter of the rectangle = 2(L+B)

= 2(20 + 15)

= 2×35

$\bf{= 70m...}$

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Thanks... ;)