Question

the length and breadth of rectangle are increased. the area by 50%. if length increased by 20%, then by what percent breadth increased?​

Answer 1

Answer:

New length = 120% of l = 6l5

New area = 150% of lb = 3lb2

New breadth :

=(3lb2×56l)=5b4

Increase in breadth :

=(5b4−b)=b4

∴ Increase % :

=(b4×1b×100)%=25%

Step-by-step explanation:

hope this helps you...

Answer 2

$let$

$length = l \\ breadth = b \\ we \: know \: area \: of \: rectangle \: \\ = l \: \times \: b$

$now \: increased \: in \: length \: by \: 20\%$

$l = 1 + 1 \times \frac{20}{100}$

$l = 1 + \frac{1}{5}$

$l = \frac{61}{5}$

$increased \: in \: area \: by \: 50\%$

$area = \: lb \: + \: lb \: \times \frac{50}{100}$

$let \: increased \: in \: breadth \: = \: b$

$now \: l \times \: b \: = \: \frac{3lb}{2}$

$= \frac{bl}{5 } \times b$

$b \: = \frac{3l \times b}{2}$

$b \: = \frac{5}{4} b$

$let \: increase \: in \: x \:$

$x\% = \frac{( \frac{5}{4} - 1)b}{b} \times 100$

$x\% = \frac{1}{4} \times 100$

$x\% = 25\%$

$i \: hope \: its \: help \: you$