Question

the length and breadth of rectangle field are 120meter and 80meter respectively. inside the field, a park of 12meter width is made around the field, the area of park is :​

Answer 1

Given:-

• Length of rectangular field = 120 m

• Breadth of rectangular field = 80 m

• Width of park inside field = 12 m

To find:-

• What's the area of park?

Solution:-

Here,we know,

$\star\:\large\boxed{\boxed{\sf\blue{Area \: of \: rectangle = l \times b }}}$

Note: As here, park is inside the field,so here area of field will be area with park.

Now we got calculation:-

★ Area with park:-

⇒ Area with park = (120 × 80) m²

⇒ Area with park = 9600 m²

$\rule{220}{1}$

Here, length & breadth will be calculated as length & breadth without park.

★ Length without park:-

⇒ Length = [ 120 - (12 + 12) ] m

⇒ Length = [ 120 - 24 ] m

⇒ Length = 96 m

★ Breadth without park:-

⇒ Breadth = [ 80 - (12 + 12) ] m

⇒ Breadth = [ 80 - 24 ] m

⇒ Breadth = 56 m

★ Now,area without park:-

⇒ Area without park = l × b

⇒ Area without park = (96 × 56) m²

⇒ Area without park = 5376 m²

★ Now area of park:-

⇒ Area of park = (Area with park) - (Area without park)

⇒ Area of park = (9600 - 5376) m²

⇒ Area of park = 4224 m²

Therefore,

$\therefore\underline{\textsf{Area of the Park is {\textbf{4224 m ^\text 2 .}}}}$

Answer 2

Answer:

⋆ DIAGRAM :

$\setlength{\unitlength}{1.5cm}\begin{picture}(8,2)\thicklines\put(7.3,2){\large{80 m}}\put(9.2,0.7){\large{120 m}}\put(8,1){\line(1,0){3}}\put(8,1){\line(0,2){2}}\put(11,1){\line(0,3){2}}\put(8,3){\line(3,0){3}}\put(8.4,2){\large{56 m}}\put(9.2,1.4){\large{96 m}}\put(8,1.26){\line(1,0){2.7}}\put(8.3,1){\line(0,2){1.76}}\put(10.7,1.25){\line(0,3){1.5}}\put(8.3,2.74){\line(3,0){2.4}}\put(8.05,1.07){\scriptsize{12}}\end{picture}$

$\rule{150}{1}$

$\underline{\bigstar\:\:\textsf{According to the Question :}}$

$:\implies\sf Area_{(Park)}=Outer\:Area-Inner\:Area\\\\\\:\implies\sf Area_{(Park)}=(L \times B)-[\{L-(12+12)\} \times\{B-(12+12)\}]\\\\\\:\implies\sf Area_{(Park)}=(120 \times 80)[\{120-24\} \times \{80-24\}]\\\\\\:\implies\sf Area_{(Park)}=9600\:m^2-[96 \times 56]\:m^2\\\\\\:\implies\sf Area_{(Park)}=9600\:m^2-5376\:m^2\\\\\\:\implies\underline{\boxed{\textsf{\textbf{Area _{\text{(Park)}} = 4224 m ^\text2 }}}}$

⠀

$\therefore\:\underline{\textsf{Area of the Park will be \textbf{4224 m ^\text2 }}}.$