Question

The length and breadth of rectangle
field are in ratio 5:3. If its perimeter is
64m. Find area of the field ?​

Answer 1

Answer:

Area of the field is 240m²

Step-by-step explanation:

Given that,

Length and breadth of a rectangle are in ratio

→ 5 : 3

The perimeter of the field is 64metres.

Step 1 :

Considering the dimensions :

→ length = "5x"

→ breadth = "3x"

Step 2 :

Perimeter of a rectangle is given by : 2(l + b)

• l (length) = "5x"
• b (breadth) = "3x"

From the given dimensions :

→ 2(5x + 3x) = 64

→ 2(8x) = 64

→ 16x = 64

→ x = 64/16

→ x = 4.

∵ The value of "x" is 4 metres.

∴ The dimensions of the rectangle are :

→ length = 5x = 5(4) = 20metres.

→ breadth = 3x = 3(4) = 12 metres.

Step 3 :

Area of rectangle : l • b

• l (length) = 20 metres.
• b (breadth) = 12 metres.

From the dimensions :

Area of the rectangle : 20 • 12

→ 240m²

∴ The area of the rectangle is 240m²

Answer 2

Answer :-

• Area of field = 240 sq.m.

Explanation :-

Given :

• The length and breadth of rectangle are in ratio 5 : 3.

• Perimeter of field = 64 m.

To Find :

• Area of field.

Solution :

Let the length and breadth be 5x and 3x.

We know that,

❖ Perimeter of Rectangle = 2(l + b).

★ According to the Question,

⇒ 2(5x + 3x) = 64 m.

⇒ 2(8x) = 64 m.

⇒ 16x = 64 m.

⇒ x = 64 ÷ 16.

⇒ x = 4.

Therefore,

• Length of Rectangle = 5x = 20 m.
• Breadth of Rectangle = 3x = 12 m.

Now, Let's Calculate Area.

❖ Area of Rectangle = l × b.

⇒ Area = 20 × 12 sq.m.

⇒ Area = 240 sq.m.

Therefore, Area of field = 240 sq.cm.