the length and breadth of rectangle field is the ratio 4 is to 3 if the area is 3072 m square find the cost of finishing the field @ rupees 4 per piece
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Answered by
3
Hi.
Here is your answer---
___________________
Let the length(l) and Breadth(b) of the Rectangular Field be 4x and 3x respectively.
Area of the Rectangular Field = 3072 m²
⇒ l × b = 3072
⇒ 4x × 3x = 3072
12x² = 3072
x² = 3072/12
x² = 256
x = 16
Thus, Length = 4x
= 4 × 16
= 64 cm.
Breadth = 3x
= 3 × 16
= 48 cm.
Perimeter of the Rectangular Field = 2(l + b)
= 2(64 + 48)
= 2 × 112
= 224 cm.
Thus, the Cost of Finishing the Field = Perimeter × Rs. 4
= 224 × 4
= Rs. 896
______________________
Hope it helps.
Have a nice day.
Here is your answer---
___________________
Let the length(l) and Breadth(b) of the Rectangular Field be 4x and 3x respectively.
Area of the Rectangular Field = 3072 m²
⇒ l × b = 3072
⇒ 4x × 3x = 3072
12x² = 3072
x² = 3072/12
x² = 256
x = 16
Thus, Length = 4x
= 4 × 16
= 64 cm.
Breadth = 3x
= 3 × 16
= 48 cm.
Perimeter of the Rectangular Field = 2(l + b)
= 2(64 + 48)
= 2 × 112
= 224 cm.
Thus, the Cost of Finishing the Field = Perimeter × Rs. 4
= 224 × 4
= Rs. 896
______________________
Hope it helps.
Have a nice day.
Answered by
11
Here is your solution
Given :-
The ratio of length and breadth of the given rectangle is 4:3
Let the length and breadth be 4x and 3x .
as area of rectangle = length × breadth
=>3072= 12x^2 =
=> 3072/12=x^2
=> 256=x^2
=>16=x
length = 4x =4×16=64m
and breadth = 3x = 3×16=48m
perimeter of the rectangle = 2 (l + b)
=> 2× (64+48)
=>224m
the cost of finishing the field @ rupees 4/m
=>224×4=Rs896
hope it helps you
Given :-
The ratio of length and breadth of the given rectangle is 4:3
Let the length and breadth be 4x and 3x .
as area of rectangle = length × breadth
=>3072= 12x^2 =
=> 3072/12=x^2
=> 256=x^2
=>16=x
length = 4x =4×16=64m
and breadth = 3x = 3×16=48m
perimeter of the rectangle = 2 (l + b)
=> 2× (64+48)
=>224m
the cost of finishing the field @ rupees 4/m
=>224×4=Rs896
hope it helps you
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