Question

the length and breadth of rectangle is 10 cm and 8 cm respectively.Find its perimeter if the length and breadth are
1)doubled
2)halved ​

Answer 1

Step-by-step explanation:

Length of the rectangle = 10 cm

Breadth of the rectangle = 8 cm

(i) When they are doubled,

⇢l = 10 × 2 = 20 cm

⇢b = 8 × 2 = 16 cm

Perimeter = 2(l + b)

= 2(20 + 16)

= 2 × 36

= 72 cm

(ii) When they are halved,

⇢l = 10/2 = 5 cm

⇢b = 8/2 = 4 cm

Perimeter = 2(l + b)

= 2(5 + 4)

= 2 × 9

= 18 cm

Answer 2

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Question:-

The length and breadth of rectangle is 10 cm and 8 cm respectively.Find its perimeter if the length and breadth are

1)doubled

2)halved

Answer:-

The length of Rectangle is 10 cm

The breadth of rectangle is 8 cm

Case 1. When length and breadth are doubled

The length of Rectangle is 20 cm

The breadth of rectangle is 16 cm

$\boxed{ \large{ \mathfrak{perimeter = 2(l + b)}}}$

Perimeter = 2 × (20 + 16) = 72 cm.

Case 2. When length and breadth is halved

Case 2. When length and breadth is halvedThe length of Rectangle is 5 cm

The breadth of rectangle is 4 cm

$\boxed{ \large{ \mathfrak{perimeter = 2(l + b)}}}$

Perimeter = 2 × (5 + 4) = 2 × 9 = 18 cm

$\huge \fcolorbox{black}{cyan}{♛Hope it helps U♛}$