Question

the length and breadth of rectangle is 4×1/5 and 3×2/3.Find the area of the rectangle.​

Answer 1

$\bold\green{\fbox{\sf{Solution}}}$

Area of any rectangle = Length × Breadth

Here,

Length = 4 whole 1/5 m = 21/5 m

Breadth = 1 whole 3/7 m = 10/7 m

So, The Area of the rectangular field is :-

$➪ \: \: Length × Breadth$

$➪ \: \: \: \: \: 21/5 m × 10/7 m$

$➪ \: \: \: \: \: \: \: 210/35 m^2$

$➪ \: \: \: \: \: 6 m^2$

Answer 2

$\huge \tt \color{red} \underline{Answer} :$
8.8 m²

$\huge \tt \color{red} \underline{Solution} :$
$\\ \large \sf\color{green} \underline{Given} :$
☞ Length = $\sf 4\frac{1}{5} = \frac{21}{5} m$
☞ Breadth = $\sf 3\frac{2}{3} = \frac{11}{3} m$

$\\ \large \sf\color{green} \underline{To \: Find } :$
☞ Area of the rectangle

$\\ \tt\color{blue} \underline{we \: know \: that, }$
$\bf Area \: of \: the \: rectangle\: = \:l×b$
$\\ \large \sf \ \ \ \ \ \ \ \ \ \ \ \ = \frac{21}{5}×\frac{11}{3} \\ \\ \large \sf \ \ \ \ \ \ \ \ \ \ \ \ = \frac{132}{15}sq.m \\ \\ \large \implies \sf \boxed{8.8}$