The length and breadth of rectangler field ate in
in ratio 4:3 ble area
is 6,912m² hind the
cast of fencing the field at 22. so permeten.
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Correct Question :-
The length and breadth of rectangular field are in ratio 4:3. If the area is 6,912 sq. m, then find the cost of fencing the field at ₹22.50 per m.
Answer :-
Cost of fencing the field = ₹7560.
Explanation :-
Given :
- Ratio of Length and Breadth = 4:3.
- Area of field = 6912 sq. m.
To Find :
- Cost of fencing the field.
Solution :
Let,
- Length of field = 4x.
- Breadth of field = 3x.
According to the Question,
L × B = Area of Rectangle.
➞ 4x × 3x = 6912 sq.m.
➞ 12x² = 6912 sq.m.
➞ x² = 6912 ÷ 12.
➞ x² = 576.
➞ x = √576.
➞ x = 24 m.
Hence,
- Length of field = 4x = 96 m.
- Breadth of field = 3x = 72 m.
We have to find the Cost of fencing the field.
So, Firstly, We have to find the Perimeter.
Perimeter of Rectangle = 2(l + b).
➞ Perimeter = 2(96 + 72).
➞ Perimeter = 2(168).
➞ Perimeter = 336 m.
Now,
Cost of fencing at 1 m field = ₹22.50.
➞ Cost of fencing 336 m field = ₹(22.50 × 336)
➞ Cost of fencing 336 m field = ₹7560.
Therefore, Cost of fencing the field = ₹7560.
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