Question

the length and breadth of rectangular field are (2x+3y) unit and (3x-y)units resp.Find the area and perimeter of the field in the form of algebraic expression​

Answer 1

Step-by-step explanation:

rectangular field => it is rectangle

L = (2x+3y)

B = (3x - y)

Area = L× B

= (2x+3y)(3x-y)

= 6x^2 -2xy +9xy -3y^2

=( 6x^2 - 3y^2 +7xy ) sq cm

Perimeter = 2(L+B)

= 2((2x+3y)+(3x-y))

= 2(5x+2y)

= 10x +4y cm

Answer 2

Given That,

$l = 2x + 3y \\ b = 3x - y$

So

____________

$area \: = \: l \times b \\ \: \: \: \: \: \: \: \: \: \: \: = > (2x + 3y)(3x - y) \\ = > 6 {x}^{2} - 2xy + 9xy - 3 {y}^{2} \\ = > 6 {x}^{2} - 3 {y}^{2} + 7xy$

____________

and also

$perimeter = 2(l + b) \\ = > 2(2x + 3y + 3x - y) \\ = > 2(5x + 2y) \\ = > 10x + 4y$

_____________

Hence you can find the area and perimeter of given rectangle