Question

The length and breadth of rectangular field in ratio 4:3the area is 6,912 m2 find the cost of fencing the field at 22.50 permeter​

Answer 1

$\huge \bf {Question}$

The length and breadth of rectangular field in ratio 4:3 the area is $\sf {{6912}^{2}}$ . Find the cost of fencing the field at ₹22.50 per meter.

$\huge \bf {Answer}$

Given,

The length and breadth of rectangular field in ratio 4:3

Area of rectangular field is $\sf {{6,912}^{2}}$

To Find,

The cost of fencing the field at ₹22.50 per meter

Formulas used,

$\fbox \green {Area\: of\: rectangle = length × breadth}$

$\fbox \green {Perimeter\: of\: rectangle = 2 (l+b) }$

Let, the length be 4x and breadth be 3x

According to the question,

$\green {=》}$Area of the field = $\sf {6,912}^{2}$

$\green {=》}$$\bf {length × breadth = 6912}$

$\green {=》}$$\bf {4x × 3x = 6912}$

$\green {=》}$$\bf {12x}^{2} = 6912$

$\green {=》}$$\bf {x}^{2} = \frac {6912}{12}$

$\green {=》}$$\bf {x}^{2} = 576$

$\green {=》}$$\bf x = {\sqrt 576}$

$\green {=》}$$\bf x = 24 m.$

Therefore,

Length of field = 4x = 4×24=96 m.

Breadth of field = 3x = 3×24=72 m.

$\fbox \green {Perimeter\: of\: field = 2(l+b)}$

$\green {=》}$Perimeter of field = 2(96 + 72)

$\green {=》}$Perimeter of field = 2 × 168

$\green {=》}$Perimeter of field = 336 m.

Hence,

$\green {=》}$Cost of fencing 1m. field = ₹22.50

$\green {=》}$Cost of fencing 336m. field=

$\green {=》}$ 336×22.50

$\green {=》}$$\fbox \green { ₹7,560}$

Answer 2

To Find,

The cost of fencing the field at ₹22.50 per meter

Perimeter of rectangle = 2 (l+b)

Let, the length be 4x and breadth be 3x

According to the question,

x = 24 m.x=24m.

Therefore,

Length of field = 4x = 4×24=96 m.

Breadth of field = 3x = 3×24=72 m.

Perimeter of field = 2(l+b)}

Perimeteroffield = 2(l+b)

=》 Perimeter of field = 2(96 + 72)

=》 Perimeter of field = 2 × 168

=》 Perimeter of field = 336 m.

Hence,

=》 Cost of fencing 1m. field = ₹22.50

=》 Cost of fencing 336m. field=

=》 336×22.50

₹7,560