Question

The length and breadth of rectangular floor is 5m and 4m.find the area of floor

Answer 1

$\huge \underline{\fbox{\fbox{Question:-}}} \\ \sf{The \: length \: and \: breadth \: of \: a \: rectangular \: floor \: is \: 5m \: and \: 4m.Find \: its \: area \: of \: the \: floor.}\\\huge \underline{\fbox{\fbox{Answer:-}}} \\ \large\bold{Given:} \\ \sf\longrightarrow{Length \: of \: the \: rectangular \: floor \: is \: 5m.} \\ \sf\longrightarrow{Breadth \: of \: the \: rectangular \: floor \: is \: 4m.} \\ \large\bold{To \: find :} \\ \sf\leadsto{Area \: of \: rectangular \: floor.} \\ \large \bold{Formula \: required:}\\ \mapsto \fbox{Area \: of \: rectangular \: floor = length×breadth} \\ \large \bold{According \: to \: question:} \\ \sf \implies{Area \: of \: rectangular \: floor = length×breadth} \\ \sf \implies{Area \: of \: rectangular \: floor =5m×4m} \\ \sf \implies{Area \: of \: rectangular \: floor = 20{m}^{2} } \\ \bold{Hence,area \: of \: rectangular \: floor \: is \: 20 {m}^{2} .} \\ \large \bold{Explore \: more:} \\ \bf \longmapsto{Perimeter \: of \: rectangle = 2(l + b)} \\ \bf \longmapsto{Area \: of \: rectangle =l \times b} \\ \bf \longmapsto{Diagonal \: of \: rectangle = \sqrt{ {l}^{2} + {b}^{2} } } \\ \large \bold{Note:Here,We \: use \: the \: l \: and \: b \: to \: specialized \: length \: and \: breadth.}$

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