Question

. The length and breadth of rectangular swimming tank is 50m and 35m respectively.
There is 2.5m wide road around the tank. Find the area of road.​

Answer 1

Answer:

450m^2

Step-by-step explanation:

• Length of the swimming pool (Inner rectangle) = 50m
• Breadth of the swimming Pool Inner rectangle)= 35 m
• Length of outer rectangle including the path = 50 + 2.5+2.5 = 55m
• Breadth of the outer rectangle '' '' = 35 + 2.5+2.5 = 40m

To Find:-

Area of Path

Solution:-

$area \: of \: outer \: rectangle = l \times b \\ 50 \times 35 = 1750 {m}^{?} \\ area \: of \: inner \: rectangle = l \times b \\ 55 \times 40 = 2200 {m}^{?} \\ area \: of \: path \: = \: area \: of \: outer \: rectangle - area \: of \: inner \: rectangle \\ 2200 - 1750 = 450 {m}^{?}$

Answer 2

Given that

• Length of swimming tank=50m
• Breath of swimming tank=35m
• There is 2.5m wide road around the tank.

To find

• Area of road

Solution

Area of PQRS= length ×Breadth

Area of PQRS= 50m×35m

Area of PQRS= 1750m²

Area of ABCD =( 50+2.5+2.5)×(35+2.5+2.5)

Area of ABCD =( 50+5)×(35+5)

Area of ABCD =55×40

Area of ABCD =2200m²

Area of road= Area of ABCD-Area of PQRS

Area of road=2200-1750

• Area of road=450m²

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