Question

The length and breadth of room ate 1075 and 825,respectively . The floo is paved with square tiles of largest possible size. The size os each tile is ---

Answer 1

✰✰|| Given ||✰✰

• Length of room = 1075

• Breadth of room = 825

✰✰|| To Find ||✰✰

• largest possible side of tiles

✪|| Solution ||✪

side of tiles = HCF of length and breadth

⇒ side of tiles = HCF of 1075 and 825

⇒ side of tiles = 25

Largest possible side of tiles is 25

Answer 2

$\blue{\bold{\underline{\underline{Answer:}}}}$

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$\green{\underline \bold{Given :}}$

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• Length of room is 1075 units

• Breadth of room is 825 units

• Room is paved with largest size square tiles.

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$\red{\underline \bold{To \: Find:}}$

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• Size of each tiles.

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$\large{\orange{\underline{\tt{Solution :-}}}}$

Length of each square side is the HCF of 1075 & 825

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Let us find the HCF by Euclid's division lemma.

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$\purple\longrightarrow$ a = bq + r where 0 ≤ r ≤ b.

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$\sf \longmapsto 1075 = 825 \times 1 + 250$

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$\sf \longmapsto 825 = 250 \times 3 + 75$

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$\sf \longmapsto 250 = 75 \times 3 + 25$

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$\sf \longmapsto 75 = 25 \times \times 3 + 0$

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Here we got the remainder as 0.

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Hence HCF is 25.

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Side of each tiles is 25 units.

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$\rule{200}5$