Math, asked by archananevare29, 1 month ago

*The length and breadth of the base of a cuboidal pool are 4.5 m and 6 m and its height is 2 m. If tiles are fitted to the base and the four walls of the pool, then what is the total area covered by the tiles?*

1️⃣ 96 m²
2️⃣ 54 m²
3️⃣ 69 m²
4️⃣ 42 m²​

Answers

Answered by sunprince0000
4

Answer

It is given that length, breadth and height of a room are 8 m, 5 m and 3 m respectively.

Area of four walls of the room is: 2h(l+b)

A=2h(l+b)=2×3(8+5)=6×13=78 m  

2

 

Area of the ceiling is:  

A=l×b=8×5=40 m  

2

 

Total area of the four walls and the ceiling of the room is 78+40=118 m  

2

 

It is given that cost of white washing is Rs.15/m  

2

, therefore,

Total cost of white washing is:

118×15=1770

Hence, the cost of white washing the walls is Rs.1770.

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