the length and breadth of the floor of a hall are 20m and 10m , respectively . square tiles of dimensions 2m are placed on the floor in three different colours. the first row of tiles on all sides is black. out of the remaining, one third are white and the rest are blue. how many blue tiles are there?
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area of floor = 20×10 m^2
=200 m^2
area of each tile = 2×2 m^2
=4 m^2
no of tiles= (area of floor)/(area of each tile)
= 200/4
= 50 tiles
no of black tiles will be 26 tiles
explanation: the floor is a rectangle.if on the two sides of 20 m there are 20 tiles ( each side 10 tiles) then other two sides of 10 m ,2 tiles will be common on the corners.So, 3 tiles each on sides of 10 m.total tiles = (10×2)+(3×2)
total tiles = 26 tiles
remaining tiles= 50-26
= 24
no of white tiles= 1/3rd of remaining
= 1/3× 24
= 8 tiles
no of blue tiles= 24 - 8
= 16 tiles
Therefore ,there are 16 blue , 8 white and 26 white tiles.
=200 m^2
area of each tile = 2×2 m^2
=4 m^2
no of tiles= (area of floor)/(area of each tile)
= 200/4
= 50 tiles
no of black tiles will be 26 tiles
explanation: the floor is a rectangle.if on the two sides of 20 m there are 20 tiles ( each side 10 tiles) then other two sides of 10 m ,2 tiles will be common on the corners.So, 3 tiles each on sides of 10 m.total tiles = (10×2)+(3×2)
total tiles = 26 tiles
remaining tiles= 50-26
= 24
no of white tiles= 1/3rd of remaining
= 1/3× 24
= 8 tiles
no of blue tiles= 24 - 8
= 16 tiles
Therefore ,there are 16 blue , 8 white and 26 white tiles.
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