Question

The length and breadth of the rectangle are (3x+2) and (x+3) units respectively. Find the area and perimeter in the form of algebraic expression.

Answer 1

Length = 3x+2
Breadth = x+3
Perimeter = 2(L+B)
=2(3x+2+x+3)
=2(4x+5)
=8x+10 units
Area = Length × Breadth
= (3x+2)(x+3)
= 3x²+9x+2x+6
=3x²+11x+6

Answer 2

The area and perimeter in the form of algebraic expression are $3x^2+12x+9$ and $6x+12$ respectively.

Step-by-step explanation:

Length of rectangle = 3x+3

Breadth of rectangle = x+3

Area of rectangle =$Length \times Breadth$

Area of rectangle =$(3x+3)(x+3)=3x^2+9x+3x+9=3x^2+12x+9$

Perimeter of rectangle =$2(l+b)=2(2x+3+x+3)=2(3x+6)=6x+12$

Hence The area and perimeter in the form of algebraic expression are $3x^2+12x+9$ and $6x+12$ respectively.

#Learn more:

The length and breadth of rectangular field are (2x+3y) unit and (3x-y) unit respectively find the area and perimeter of the field in the form of algebraic expression​

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