Question

The length and breadth of the rectangle is (4a + 2b) cm and (3a - 7b) cm respectively .Find the perimeter of the rectangle​

Answer 1

Given:

• Length of Rectangle = (4a+2b)cm
• Breadth of Rectangle = (3a-7b)cm

Explanation:

Rectangle is a type of Quadrilateral in which all angles measure 90°.

࿋ Area of Rectangle = Length×Breadth

࿋ Perimeter of Rectangle = 2(l+b)

☞ In Rectangle opposite sides are equal and diagonals bisect each other.

Solution:

$→\;{\sf{2[(4a+2b)+(3a-7b)]}}$

$→\;{\sf{2[(4a+3a)+(2b-7b)]}}$

$→\;{\sf{2(7a-5b)}}$

$→\;{\bf{14a-10b}}$

.:. Perimeter of Rectangle ➝ $\red{\bold{(14a-10b)}}$

✯MrPrince࿐