Math, asked by nitin4953, 1 month ago

The length and breadth of the rectangular seating area of marriage hall
is in the ratio 9:7. The total perimeter of the seating area is 120 m. How
many chairs can be placed in the hall, if a chair with an occupant takes
2500 cmof area?​

Answers

Answered by mgmmoviegamemuzic
0

Answer:

Here, l=(5.7±0.1)cm,b=(3.4±0.2)cm

Area, A = l×b=5.7×3.4=19.38cm

2

=19.0cm

2

(rounding off to two significant figures)

A

△A

=±(

l

△l

+

b

△b

)

= ±(

5.7

0.1

+

3.4

0.2

)=±(

5.7×3.4

0.34+1.14

)=±

19.38

1.48

⇒△A=±

19.38

1.48

×A=±

19.38

1.48

×19.38=±1.48

△A=±1.5 (rounding off to two significant figures);

Area = (19.0±1.5)cm

Step-by-step explanation:

Here, l=(5.7±0.1)cm,b=(3.4±0.2)cm

Area, A = l×b=5.7×3.4=19.38cm

2

=19.0cm

2

(rounding off to two significant figures)

A

△A

=±(

l

△l

+

b

△b

)

= ±(

5.7

0.1

+

3.4

0.2

)=±(

5.7×3.4

0.34+1.14

)=±

19.38

1.48

⇒△A=±

19.38

1.48

×A=±

19.38

1.48

×19.38=±1.48

△A=±1.5 (rounding off to two significant figures);

Area = (19.0±1.5)cm

Answered by satyam09s0205
0

Answer:

... We cannot simply divide the total area of the banquet hall by ... Who will be seated at the top table and sprigs w

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