the length and breadth ofa rectangular field are in the ratio of 7:4 the cost of fencingthe field at rupees 25 per metre rupees 3300 find the dimension of the field
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let the sides be 7x and 4x
perimeter=3300/25=132m
PERIMETER=2(L+B)
132=2(7X+4X)
66=11X
X=6
SO SIDES ARE 42METRE AND 24METRES
perimeter=3300/25=132m
PERIMETER=2(L+B)
132=2(7X+4X)
66=11X
X=6
SO SIDES ARE 42METRE AND 24METRES
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