Question

The length and breath are in the ratios of 3: 2 if the perimeter of the field is 250 m find the cost of reaping the field at ₹ 15 per 50₹

Answer 1

length: breadth = 3 : 2

let the constant ratio be 'x' ,


perimeter = 250m

2( length + breadth) = 250

2( 3x + 2x) = 250

10x = 250 => x = 25

length= 3x = 3× 25 = 75m

breadth= 2x = 2 × 25 = 50m

area of the field= 75 × 50 = 3750m^2

cost of reaping 1m^2 = ₹15


cost of reaping the field
= 15 × 3750 = ₹56250

Answer: cost of reaping = ₹56250

Answer 2

let x be the ratio between the length and breadth.

so , length = 3x

and , breadth = 2x

Perimeter = 250 m

$\bf=> 2 (length + breadth) = 250 \\ \\ \bf=> 2 (3x + 2x) = 250 \\ \\ \bf=> 2 × 5x = 250 \\ \\ \bf=> 10x = 250 \\ \\ \bf= > x = \frac{250}{10} \\ \\ \bf = > x = 25m$

so , length = 3x = 3× 25 = 75m

and , breadth = 2 × 25 = 50cm

$\bf\therefore \: area \: of \: rectangle \:$

$\bf= length \times breadth \\ \\ \bf= 75 \times 50 \\ \\ \bf = 3750 \: {m}^{2}$

Now ,

given : cost of reaping per m² = ₹15

so , cost of reaping the field of 3750m² = 3750 × 15 = ₹56250