Question

The length and breath of a field are 22.4 cm and 15.8 cm respectively and have been measured to an accuracy of 0.2 cm. find the error in the area of the field.

Answer 1

Answer: The correct answer is 2.09%.

Explanation:

The expression for the area of the rectangle.

A=LB

Here, L is the length and breadth of the rectangle.

Calculate the error in the area of the field.

$\frac{\delta A}{A}\times 100=\frac{\Delta L}{L}\times 100+\frac{\Delta B}{B}\times 100$

It is given in the problem that the length and breath of a field are 22.4 cm and 15.8 cm respectively and have been measured to an accuracy of 0.2 cm.

Put L= 22.4 cm, B= 15.8 cm and $\Delta L= 0.2 cm$ and  $\Delta B= 0.2 cm$ .

$\frac{\delta A}{A}\times 100=\frac{ 0.2}{22.4}\times 100+\frac{0.2}{15.8}\times 100$

$\frac{\delta A}{A}\times 100= 2.09%$

Therefore, the error in the area of the field is 2.09%.

Answer 2

Explanation:

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