Question

The length and breath of a rectangle are (a+5b) units and (7A-B) units
respectively the perimeter of this rectangle is equal to the Perimeter of a square .find how much is the area of the rectangle less than that of the square

Answer 1

Answer:

perimeter of rectangle=2(l+b)

2(a+5b+7a-b)

2a10b+14a-2b

​p=16a-8b=the area of square

therefore side of square 16a-8b divided by 4

4a+2b=side of square

area of square =4a+2bX4a+2b

(a+b)2=a2+2ab+b2

so area =16a2​+16ab+4b2    (1)

area of rctangle =lXb=(a+5b)X(7a-b)

=7a2-ab+35ab-5b2       (2)

(1)-(2)=9a2-18ab+9b2  this much is the area of rectangle less than that of square

Step-by-step explanation:

I hope this helps.