the length and breath of a rectangular field are in the ratio 5:3. If it's perimeter is 128m, find the dimensions of the field.
Maurya93:
let the dimensions be 5x and 3x. so, perimeter=2(l+b)=2(5x+3x)=128. ... 2×8x=128. =8x=64. x=8. hence dimensions are 5x=(5×8)=40 cm , 3x=(3×8)= 24 cm
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Answered by
14
128/(5+3)=16
16*3=48
16*5=80
Dimensions_48 and 80
16*3=48
16*5=80
Dimensions_48 and 80
Answered by
27
The length and the breadth of a rectangle field are in the ratio 5:3, if its perimeter is 128m.
The dimensions of the field.
Let the ratio be R.
We know that perimeter of rectangle: 2(length + breadth)
→ 2(5R + 3R) = 128
→ 2(8R) = 128
→ 16R = 128
→ R =
→ R = 8m.
Now,
- The dimensions of the field:
The length of rectangular field = 5(8)m = 40m.
The breadth of rectangular field = 3(8)m = 24m.
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