Question

The length and breath of a rectangular hall in a school are 20m and 16m respectively. Rectangular tiles of length 50cm and width 40cm are to be fixed on its floor. How many tiles will be required? Find the cost of fixing the tiles at the rate of rs15 per sq m.

Answer 1

area=l×b
=320m^2
area of 1 tile
=0.5×0.4
=0.2

total tiles into cost
=
$\frac{area \: of \: room}{area \: of \: tile} \\ \frac{320}{0.2} \\1600$
rate=15×320
=4800

Answer 2

area of the hall = l*b=20*16=320 sq.m
area of the tile  = l*b=50*40=2000 sq.cm=20 sq.m
no.of tiles needed= 320/20= 1600 tiles
cost = 15*320 = 4800rs
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